Tag: IPv4

  • Fragmentation

    IP Fragmentation Lab – Overview and Setup

    This lab focused on exploring the behavior and structure of IP fragmentation. The exercises require close analysis of fragmented IP packets using either Wireshark or tcpdump.

    Exercise 1 – Analyzing the First Two IP Fragments

    Look at the first two records. They are related fragments and are the only ones associated with this pair of fragments. What do you think happens when they are sent?

    After identifying the first two packets as related IP fragments, I needed to confirm whether the full set of fragments was present. I used the following tcpdump command to examine fragmentation details more closely:

    Both packets showed more fragments flag set (flags [+]), but neither was marked as the last fragment (with offset and MF flag = 0). This means that the packet reassembly could not be completed, as at least one fragment was missing from the set.

    To see how the system reacts to this failed reassembly, I looked for an ICMP error message that might be triggered by this condition. I ran:

    Sure enough, shortly after the two fragment packets, I found an ICMP “Time Exceeded – Fragment Reassembly Time Exceeded” message. This type of ICMP error is sent when the receiver cannot finish reassembling a fragmented IP packet within the allowed time window.

    The error response appeared in record 14, indicating the network’s handling of incomplete fragmentation and how it alerts the sender when reassembly fails.

    Why didn’t records 3 and 4 (a different pair of related fragments) generate the same type of ICMP error message?

    To answer this, I examined the fragmentation details of records 3 and 4. Although they represent another pair of related fragments, neither one has a fragment offset of 0. The packet corresponding to the third record has an offset of 1480. This is important because only the first fragment (offset 0) contains the protocol field, which identifies the embedded protocol (like ICMP, TCP, etc.).

    Without that first fragment, the receiving system can’t determine what protocol the original datagram was using. As a result, it doesn’t send an ICMP “Fragment Reassembly Time Exceeded” message, since it lacks the context needed to generate one.

    Exercise 2 – Identifying Fragment Overlap and Suspicious Packet Behavior

    In this exercise, I analyzed packets 5, 6, and 7, which appeared to be related fragments. At first glance, they looked like they might belong to a single fragmented IP packet, but something unusual stood out.

    Fragment Overlap Issue
    Packets 5 and 6 both have a fragment offset of 0, meaning they are both marked as the first fragment. However, they have different total lengths, which would cause them to overlap if processed together. Packet 7 appears to be the final fragment in this set, but it overlaps with packet 6 based on its offset and length.

    This kind of fragment overlap can be interpreted differently depending on the operating system, making it a potential tactic for evasion or exploitation. Some systems may discard the entire packet, while others may accept whichever version arrives first or last.

    Suspicious IP Options
    I also noticed that all three packets contained IP options, which are uncommon in typical traffic and can signal malicious activity. Specifically, the packets include type 131 IP options, which are often used to route packets through specific network paths. This could be an attempt to bypass firewalls, intrusion detection systems, or route traffic through an attacker-controlled device.

    Exercise 3 – Spotting Crafted Fragment Sets

    What makes you believe that the set of fragments in records 8–13 (IP ID 31026) have been crafted? Identify five abnormal traits.

    Upon analyzing these packets, it became clear that these fragments were likely intentionally crafted rather than the result of legitimate fragmentation. I identified several suspicious traits that support this conclusion:

    1. The second packet does not have a More Fragment flag which would indicate that this is the last packet of this fragment train when in fact there are more packets that are part of this train following this packet.
    2. The second to last packet does not have the same payload size a nd total length size as the fragments before him. All fragments should be the exact same size outside of the last fragment.
    3. The 4th and 5th fragments are overlapping (they have the same offset of 24).
    4. All the packets have payloads of size 8 and 16 bytes and total length of 28 and 36 bytes. There should be no MTU that small and causing fragmentation to occur.
    5. There is a fragment missing before the last fragment. We go from offset 24 to offset 48 while the payload size is only of 8 bytes. We should have a fragment with an offset 32 that is missing.

    Exercise 4 – Filtering for ICMP Echo Request Fragments

    In this exercise, I used a tcpdump filter to try and identify all fragments related to ICMP echo requests (type 8). The command provided was:

    Why don’t we see all the fragments associated with the echo requests ?

    Only fragments with an offset of 0 include the ICMP header (which contains the type field). Subsequent fragments—those with a non-zero offset—contain only payload data, not the protocol header. As a result, the filter doesn’t match those fragments, because the ICMP type field isn’t present in their portion of the packet.

    To capture all fragments of a given ICMP echo request, I would need to filter by IP ID (the identifier field) rather than by protocol fields. That’s because all fragments of a packet share the same IP ID, allowing me to track the complete set regardless of whether they include the ICMP header.

  • IPv4

    Lab 1.4 – IPv4 Packet Analysis

    This lab focused on examining network traffic at the IPv4 layer, with an emphasis on identifying abnormal or suspicious behavior within the packet capture.

    Lab Setup

    For this exercise, I used the capture file called ipv4.pcap.

    Once downloaded, I opened the file in Wireshark and began my analysis.

    Exercise 1 – Analyzing the First IPv4 Packet

    a) What version of IP is the first packet?

    We can find this either by looking at the Ethernet header or the IP header. Looking at the IP Header, the IP version is located in the higher-order nibble of the 0 byte offset. We can see there that this is an IPv4 packet.

    b) What is the IP Time To Live value, in decimal, in this packet?

    To answer this, I examined the IPv4 header of the first packet in the ipv4.pcap file. I specifically looked at the Time To Live (TTL) field, which determines how many hops (routers) the packet can pass through before being discarded.

    The TTL field is located 8 bytes into the IP header, but Wireshark conveniently displays this value directly in the decoded packet details. In this case, the TTL value was 64, which is a common default for Linux-based systems.

    This value can also give clues about the operating system or network behavior based on how far the packet has traveled.

    c) What is the source IP address, in hexadecimal, in the first packet?

    To find the source IP address in hexadecimal, I examined the IPv4 header in the first packet of the ipv4.pcap capture. The source IP address is located between bytes 12 and 15 from the start of the IP header.

    Wireshark makes this easy by displaying both the decimal and hexadecimal representations. For the first packet, the source IP is 192.168.11.65 in decimal, which corresponds to 0xc0 0xa8 0x0b 0x41 in hexadecimal.

    d) What is the destination IP address, in hexadecimal, in the first packet?

    To find the destination IP address in hexadecimal, I examined the IPv4 header of the first packet in the ipv4.pcap file. According to the IP header structure, the destination IP is stored between bytes 16 and 19 from the start of the IP header.

    Wireshark clearly shows this value in both hexadecimal and decimal. In this case, the destination IP is 192.168.1.1, which corresponds to the hexadecimal representation 0xc0 0xa8 0x01 0x01.

    Exercise 2 – Identifying Abnormalities in the IPv4 Header

    In this exercise, I examined the second packet in the ipv4.pcap capture and identified two key problems with its IP header.

    Problem 1: Invalid IP Version
    The first issue is that the IP header lists version 8, which is not a valid or supported IP version. Only versions 4 and 6 are in use today. Because of this, Wireshark marks the packet in red and does not attempt to decode it further.

    Problem 2: Invalid Header Checksum
    After inspecting the raw packet bytes, I found another issue in bytes 10 and 11, which represent the IP header checksum. The value was 0x0000, which is invalid and indicates the packet may have been corrupted or crafted improperly.

    Impact
    Both of these abnormalities would cause the packet to be dropped immediately by the first router or system it attempts to pass through. This exercise helped me understand how malformed packets are detected and discarded at the network layer.

    Exercise 3 – Hex Analysis Using tcpdump

    In this part of the lab, I used the tcpdump command-line tool to inspect raw packet data and answer questions related to the third packet in the ipv4.pcap capture.

    To extract the first few packets in hexadecimal format, I ran:

    a) What version of IP is this packet? What is the header length if the packet ?

    By looking at the raw hexadecimal output of the third packet, I found it starts with the byte 0x45. This first byte breaks down into two nibbles:

    • 4 → IP version
    • 5 → header length

    So, the version number of this packet is IPv4, as indicated by the high-order nibble of the first byte.

    The header length field is in units of double word so it has to be multiplied by 4 to be converted to a length of 20 bytes.

    b) What is the embedded protocol in this packet, according to the IP header?

    To determine the embedded protocol, I examined byte offset 9 in the IP header of the third packet. This byte indicates which protocol is encapsulated within the IPv4 packet.

    Using the tcpdump output, I located the value at this offset. For this packet, the value was 0x01, which corresponds to ICMP (Internet Control Message Protocol).

    Exercise 4 – Calculating ICMP Header and Data Length

    In this task, I analyzed the fourth packet in the ipv4.pcap file to determine how many bytes were used by the ICMP header and data, following the IPv4 header.

    To do this, I used two values from the IP header:

    • Total Length: 68 bytes (it is found in the 3rd byte offset of the IP Header // it has a hexadecimal value of 0x44)
    • Header Length: 20 bytes (which is shown as a value of 5 in the header, multiplied by 4)

    By subtracting the IP header length from the total IP datagram size:
    68 - 20 = 48 bytes

    So, the ICMP header and data together occupy 48 bytes in this packet.